The Tee Attenuator conversion calculator determines the resistor values R1 and R2 for a T-type attenuator network based on the required attenuation and characteristic impedance. It helps RF engineers design precise attenuators that reduce signal levels while maintaining impedance matching between connected components.
Formulas
R1 = Z0 * ( ( 10^(dB/20) – 1 ) / ( 10^(dB/20) + 1 ) )
R2 = 2 * Z0 * ( 10^(dB/20) / ( 10^(dB/10) – 1 ) )
Formula Explanation
- Z0 represents the system characteristic impedance, typically 50 Ω or 75 Ω.
- dB is the desired attenuation in decibels.
- R1 are the series resistors, while R2 is the shunt resistor between them.
- The network provides symmetrical attenuation while preserving impedance matching.
Uses of this calculator
- Designing Tee attenuators for RF, microwave, and audio circuits.
- Setting signal attenuation levels while maintaining impedance consistency.
- Preventing signal reflections and power mismatch in transmission lines.
- Creating test setups and calibration networks in communication systems.
What are the resistor values for a 10 dB Tee attenuator in a 50-ohm system?
Input: Attenuation = 10 dB, Z0 = 50 Ω
Output:
- R1 = 50 * ( (10^(10/20) – 1) / (10^(10/20) + 1) ) = 50 * ( (3.162 – 1) / (3.162 + 1) ) = 50 * (2.162 / 4.162) = 25.96 Ω
- R2 = 2 * 50 * ( 10^(10/20) / (10^(10/10) – 1) ) = 100 * (3.162 / (10 – 1)) = 100 * 0.351 = 35.1 Ω
- Required resistors: R1 = 25.96 Ω, R2 = 35.1 Ω