The Bridged Tee Attenuator conversion calculator determines the resistor values needed to design a bridged tee attenuator for a given impedance and desired attenuation. This network is often used in RF and microwave circuits to reduce signal levels while maintaining constant impedance across the input and output ports.
Formulas
R1(Ω) = Z0 * [10^(dB/20) – 1]
R2(Ω) = Z0 / [10^(dB/20) – 1]
Formula Explanation
- R1 is the series resistor placed between the source and load.
- R2 is the shunt resistor forming the bridge in the attenuator network.
- Z0 is the system impedance, typically 50 Ω or 75 Ω in RF systems.
- dB represents the desired attenuation level in decibels.
- The formulas ensure both input and output impedances remain matched to Z0, minimizing reflections and preserving signal integrity.
Uses of this calculator
- Designing attenuators for RF and microwave circuits.
- Creating precision test setups with accurate impedance matching.
- Reducing signal amplitude in transmitter or receiver chains.
- Developing matching networks and low-reflection terminations.
What are the resistor values for a 10 dB bridged tee attenuator with 50 Ω impedance?
Input: Attenuation = 10 dB, Z0 = 50 Ω
Output:
- R1 = 50 * [10^(10/20) – 1] = 50 * (3.162 – 1) = 50 * 2.162 = 108.1 Ω
- R2 = 50 / [10^(10/20) – 1] = 50 / 2.162 = 23.1 Ω
- R1 = 108.1 Ω, R2 = 23.1 Ω